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langchain-reference-architecture

100 / 100 · Low risk

Fine to try.

By Dicklesworthstone/pi_agent_rust (GitHub) · coding · 1,992 stars · scanned at commit 07fc1e0

Implement LangChain reference architecture patterns for production. Use when designing LangChain systems, implementing scalable patterns, or architecting enterprise LLM applications. Trigger with phrases like "langchain architecture", "langchain design", "langchain scalable", "langchain enterprise", "langchain patterns".

Works with any agent that supports SKILL.md skills.

What this skill can do

We found nothing in the files we read that matches our rules. That does not prove the skill is safe: see the limits of static scanning.

Install

Paste this into your terminal. It downloads exactly the version we scanned, not whatever is newest.

if [ -e ~/.agents/skills/'langchain-reference-architecture' ] || [ -L ~/.agents/skills/'langchain-reference-architecture' ]; then echo 'A skill folder named langchain-reference-architecture already exists — not replacing it' >&2; false; else d=$(mktemp -d) && git clone --quiet --filter=blob:none --no-checkout 'https://github.com/Dicklesworthstone/pi_agent_rust' "$d" && git -C "$d" checkout --quiet '07fc1e0b82ab6a16e694a0e00a36767e9f23cf1b' -- 'tests/ext_conformance/artifacts/plugins-community/plugins/saas-packs/langchain-pack/skills/langchain-reference-architecture' && mkdir -p ~/.agents/skills && cp -R "$d"/'tests/ext_conformance/artifacts/plugins-community/plugins/saas-packs/langchain-pack/skills/langchain-reference-architecture' ~/.agents/skills/'langchain-reference-architecture' && rm -rf "$d"; fi

Codex reads ~/.agents/skills directly. For Claude Code, Cursor, Copilot, Gemini CLI, Antigravity or OpenCode, also link it. For Claude Code: ln -s ~/.agents/skills/'langchain-reference-architecture' ~/.claude/skills/'langchain-reference-architecture' (other agents: ~/.cursor/skills, ~/.copilot/skills, ~/.gemini/skills, ~/.gemini/config/skills, ~/.config/opencode/skills). Or install through the finder skill, which does both.

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